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$F(9,0)$. In the first equation $2x+y = 7$, taking $x = 0$, we get $y = 7$. The value of $Z$ ate $R(0,10)$ is $Z= 30 + 510=50$. e.
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Once this function is created, it will continue to increase until it reaches the maximum value that the program originally defined. The feasible region is an unbounded space. The corner points of the feasible region are:The maximum value of the objective function $Z$ is 24 which is at $P(3/2,6)$ and $Q(5,4/3)$. 4$ and $y=2. The coordinates of $P$ are $(3/2,6)$. 8) = 31.
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The process goes on through the HG-edge up to G-vertex, obtained data are shown in tableau IV. e. ADM2302 ~ Rim JaberAlternate Optimal Solutions (Cont’d) • Consider the following example: Max 3X1 + 2X2 Subject to 6X1 + 4X2 = 24 X1 = 3 X1, X2 = 0 ADM2302 ~ Rim JaberAn Example of Alternate Optimal Solutions 8 7 6 5 4 3 2 1 0 Optimal Solution Consists of All Combinations of X1 and X2 Along the AB Segment A Isoprofit Line for $8 Isoprofit Line for $12 Overlays Line Segment B AB 1 2 3 4 5 6 7 8 ADM2302 ~ Rim JaberExample: Alternate find here Solutions • At profit level of $12, isoprofit line will rest directly on top of first constraint line. The linear programming problem can be particularly challenging to solve because it involves an assumption about the nature of the universe.
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Hence there is no feasible solution to the given linear programming problem. If you leave any information out of this input or equation, then you may find out very soon after completing the assignment that the answer that you receive from the linear programming equation is incorrect. Identify an optimal solution as a corner point with highest profit (maximization problem), or lowest cost (minimization). i. , $B(1000,0)$.